Thomas O'Sullivan's Mathematics & Physics Pages

Uniformly Accelerated motion

A particle moving in a straight line with constant acceleration passes three points p, q, r and has speeds u and 7u at p and r respectively. - Find its speed at the midpoint of [pr] in terms of u.
- Show that the time from p to q is twice that from q to r.
Solution: Between p and q v Between q and r (7u) Þ 49u Then getting rid of 2ax gives: v 49u - 49u
^{2}– v^{2}= v^{2}– u^{2} - v = 5u
(ii) Applying the formula v = u + at to each half: Between p and q: 5u = u + at Þ t Between q and r: 7u = 5u + at Þ t i.e. t |
1995 Q. 1(b) A juggler throws up six balls, one after the other at equal intervals of time t, each to a height of 3m. The first ball returns to his hand t seconds after the sixth was thrown up and is immediately thrown to the same height, and so on continually. (assume that each ball moves vertically). Find - the initial velocity of each ball
- the time t
- the heights of the other balls when any one reaches the juggler’s hand.
Solution |

© T O’Sullivan 1999 ( http://homepage.eircom.net/~phabfys )